
Initial condition
- H2(g): 0.70 mol
- He(g): 1.00 mol
- Li(s): 0.40 mol (still solid: it melts at 180.5 degrees)
- LiH(s): 0.60 mol
- Pressure = 525.5 kPa
- Temperature = 99°C
No reactions!
Beryllium doesn’t react with any of the things in the vessel: H2(g), He(g), Li(s) or LiH(s). My one mole of beryllium powder (which would cost me over $70) would just sit at the bottom of the vessel doing nothing.
With not much else to write about in the Periodic Table Smoothie this week, it might be a good idea to calculate how much this Periodic Table Smoothie would have cost in real life.
Element | Cost per kg[1] | Molar mass | Cost per mole |
H2 | $ 4.00 | 2 | $ 0.008 |
He | $ 52.00 | 4 | $ 0.21 |
Li | $ 270.00 | 6.941 | $ 1.87 |
Be | $ 7,840.00 | 9.01 | $ 70.64 |
B (next week) | $ 11,140.00 | 10.811 | $ 120.43 |
TOTAL cost of 1.00 mol of each of the first five elements | $ 193.16 |
Conclusion
The addition of beryllium was highly uneventful. The vessel still contains the following:
- H2(g): 0.70 mol
- He(g): 1.00 mol
- Li(s): 0.40 mol (still solid: it melts at 180.5 degrees)
- LiH(s): 0.60 mol
- Pressure = 525.5 kPa
- Temperature = 99°C
We’ll add boron next week and see what happens.
Wouldn’t the pressure and possibly temperature increase, or is the mass too dense to make much of a difference in pressure?
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Temperature of the vessel and its contents is fixed in this experiment. Pressure increases and this is documented in the article.
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I’m seeing the contents of the vessel at the end of the article being identical to the initial contents (before Be), with the pressure of both being 525.5 kPa.
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Yes. Nothing happened when we added beryllium.
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