### Initial condition

• H2(g): 0.70 mol
• He(g): 1.00 mol
• Li(s): 0.40 mol (still solid: it melts at 180.5 degrees)
• LiH(s): 0.60 mol
• Pressure = 525.5 kPa
• Temperature = 99°C

### No reactions!

Beryllium doesn’t react with any of the things in the vessel: H2(g), He(g), Li(s) or LiH(s). My one mole of beryllium powder (which would cost me over \$70) would just sit at the bottom of the vessel doing nothing.

With not much else to write about in the Periodic Table Smoothie this week, it might be a good idea to calculate how much this Periodic Table Smoothie would have cost in real life.

 Element Cost per kg[1] Molar mass Cost per mole H2 \$              4.00 2 \$       0.008 He \$            52.00 4 \$       0.21 Li \$          270.00 6.941 \$       1.87 Be \$      7,840.00 9.01 \$    70.64 B (next week) \$    11,140.00 10.811 \$  120.43
 TOTAL cost of 1.00 mol of each of the first five elements \$        193.16

Conclusion

The addition of beryllium was highly uneventful. The vessel still contains the following:

• H2(g): 0.70 mol
• He(g): 1.00 mol
• Li(s): 0.40 mol (still solid: it melts at 180.5 degrees)
• LiH(s): 0.60 mol
• Pressure = 525.5 kPa
• Temperature = 99°C

We’ll add boron next week and see what happens.

## 4 thoughts on “Let’s add beryllium powder”

1. Mike C says:

Wouldn’t the pressure and possibly temperature increase, or is the mass too dense to make much of a difference in pressure?

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1. Temperature of the vessel and its contents is fixed in this experiment. Pressure increases and this is documented in the article.

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1. mcattle says:

I’m seeing the contents of the vessel at the end of the article being identical to the initial contents (before Be), with the pressure of both being 525.5 kPa.

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