## 16 thoughts on “suvat-rearranged”

1. Arnold says:

When working U out without V Numerator should read 2S-at^2 🙂

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1. William Dissing says:

and same with working V out without U

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1. Lynee says:

Is it 2s-at^2 or 2s+at^2 when finding V without U?

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2. samaritan says:

top right equation is incorrect, should be minus v^2

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1. Malik says:

no its not other wise the answer is always 0

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3. tmmm says:

you rearranged s=u^2+V^2/2a wrong

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4. Meha says:

This is confusing, i cannot figure out U without v and s

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5. S Moodley says:

Equation for u without v is also incorrect, should read u=(s-0.5at(squared))/t. You’d be better off starting with the original equations and rearranging them. This also helps reinforce the equations in your head and you become quicker in the exam! Great idea though!

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6. Chaim says:

equation 4 along and 1 down should have a minus:
you have:
s = (t/2)(u+v)
therefore:
u = (2s/t) – v

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7. Gary says:

The top right equation is wrong and should be corrected.
s = (v^2 – u^2) / 2a

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8. Gary says:

The Equation to the right of the “U” is also wrong.
u = s – at^2 / 2t will provide incorrect results.

u = (s – 1/2 at^2) / t

I wonder how many students have lost marks using this cheat sheet?
Although not many problems tend to ask you to calculate initial velocity “u” the sheet should be corrected if you want to leave it online.

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9. Gary says:

3rd and final correction from me (right hand column, 2nd row):
u = SQR (2as – v^2) is wrong as the number to be squared will be negative.

Correct formula should read u = SQR (v^2 – 2as)

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10. Candice says:

2nd column, 3rd down, should read v = (2s+at^2)/2t
Both uses of the quadratic equation should be plus or minus.
4th column, 2nd down should be u=(2s/t) – v

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11. steve says:

He is merely a chemist folks…

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12. Edward says:

you’ve rearranged them incorrectly

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